An alloy contains 36 % of bronze. What quantity of alloy is required to get 340 g of bronze? (A) 944.4 (B) 1500 (C) 950 (D) 980.5►Correct Option Correct Answer is: ALet the quantity of alloy required = x g Then 36 % of x =340 g ⇒ 36/100 × x = 340 g x = (340 × 100)/36 g x = 34000/36 g x = 944.4 g