(A) $495
(B) $500
(C) $540
(D) $650
Correct Option is: A
Let the sums of money received by A, B and C be x, y and z respectively.
Then x – 10 : y – 20 : z -15 is 11a : 18a : 24a
When $10, $20 and $15 are removed, we are removing a total of $45 from $1105.
Therefore,
11a+18a+24a=1105-45=1060
53a=1060
or a= 20
We know that z – 15 = 24a = (24 * 20) = 480
Therefore, z = 480 + 15 = $495