Ratio and Proportion Online Test 1

IBM initially quoted Rs 7x lakh. KTC quoted 4x lakh.
IBM’s final quote =(4x−1) Lakh
Thus, (4x-1/4x) = 3/4 = x = 1
IBM’s bid winning price = Rs 3 Lakh
So IBM wins the bid at 4x−1= Rs 3 lakh.

Let the sums of money received by A, B and C be x, y and z respectively.
Then x – 10 : y – 20 : z -15 is 11a : 18a : 24a
When $10, $20 and $15 are removed, we are removing a total of $45 from $1105.
Therefore,
11a+18a+24a=1105-45=1060
53a=1060
or a= 20
We know that z – 15 = 24a = (24 * 20) = 480
Therefore, z = 480 + 15 = $495

1) 20% profit at the price of 7 cents means that cost of the mixture should be 70/12 cents per ounce (7 =
120% and x = 100% => x = 7*100/120)
2) Let the amount of 5 cent rice will be x and the amount of 6 cent one – y. The price of ounce of mixture will
be: (5x + 6y)/(x + y), which as we know should equal to 70/12
3) (5x + 6y)/(x + y) = 70/12 => x/y = 1/5

Let AA’s income be = 4x
AA’s expenses, therefore = 4x–25
Let BB’s income be = 5x
BB’s expenses, therefore = 5x–50
We know that the ratio of their expenses = 5:6
⇒24x−150=25x−250
⇒ Therefore, x=100
A’s income =4x=400 and B’s income =5x=500

The sum of the marks=6x+5x=11x
But the sum of the marks is given as 275=11x. We get x=25x=25 therefore, John marks is 6x=1506x=150
and Smith marks = 5x=125.
Therefore, the combined average of their marks % = 150+1252=137.5
If the total mark of the exam is 100 then their combined average of their percentage is 68.75
Therefore, if their combined average of their percentage is 137.5 then the total marks would be
137.568.75×100=200

Let the stones with Michael, Johnson and David be m,r and b respectively.
Given, 5r = 7m and 5m = 7b
⇒25r = 35m and 35m = 49b
⇒25r = 35m = 49b = k
The least possible integral values for r, m, b will be r = 49, m = 35 and b = 25
Total = 49 + 35 + 25 = 109.

The ratio of the share students : teacher: benefactor=1:1.5 : 4.5
So the proportion to teacher’s share = 1.5/7
Hence, the teachers would donate 1.5/7×4200=Rs 900

8 times AA’s share = 12 times BB’s share = 6 times CC’s share
Note that this is not the same as the ratio of their wages being 8:12:68:12:6
In this case, find out the L.C.M of 8, 12 and 6 and divide the L.C.M by each of the above numbers to get the
ratio of their respective shares.
The L.C.M of 8, 12 and 6 is 24.
Therefore, the ratio A:B:C= 24/8: 24/12: 24/6
A:B:C=3:2:4
The sum of the total wages = 3x + 2x + 4x = 432 => 9x = 432 or x = 48.
Hence, A who gets 3x will get 3 * 48 = Rs.144.

Since the ratio of the number of Rs. 1, 50p and 25p coins can be represented by 3 consecutive odd numbers
that are prime in ascending order, the only possibility for the ratio is 3:5:7.
Let the number of Re1, 50p and 25p coins be 3k, 5k and 7k respectively.
Hence, total value of coins in paise
⇒ 100×3k+50×5k+25×7k=725k=5800
⇒ k=8.
If the number of coins of Rs. 1,50p and 25p is reversed, the total value of coins in the
Bag (in paise) =100×7k+50×5k+25×3k=1025k (In above we find the value of k).
⇒ 8200p
= Rs 82.

Number of turns required= 80 × 54/32 × 8/45 = 24
24 times