Problems on Trains Online Test 1

Given that,
The speed of the train = 25km/hr
= 25x 5/18 m/sec
= 125/18 m/sec
The train crosses a scooter in 12 seconds. Then,
Length of the train = 125/18*12= 83.33
Now, let the length of the platform is X m.
the train crosses the platform in 20 seconds.
Then, (X +83.3)/20 = 125/18
18(X +83.3)= 2500
18X=1000.6
X=55.58 m
Hence the platform is 55.58 m long.

Length of the train = 170 m
Length of the bridge = 80 m
Therefore, length of the train + length of the bridge = (170 + 80) m = 250m
Speed of the train = 22.5 km/hr
Speed of the train = 22.5 × 5/18 m/sec
= 112.5/18m/sec
= 6.25m/sec
Therefore, time taken by the train to cross the bridge = 250 m/6.25 m/sec. = 40 seconds

Speed of the train = 270 km/hr.
Converting the speed into m/sec
Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec
First, we have to find the length of the train
Let the length of the train be X km.
Given that, the time taken to cover 700 meters = 240 seconds.
We can have, distance/speed = time
x+700/75 = 240
x+700 = 18000
x = 17300 m
The time taken by the train of length 17300 meters to cross a standing Pole at 75 m/s =( 17300/75)seconds
= 231 seconds.
Hence the answer is 231 sec(approx.)

Time taken to cross the bridge(12 km) = 600 seconds.
Speed of the train = Distance / Time
= 12/600 km/s
= 12000/600 m/s
= 20m/s
Train crosses a girl in 24 seconds.
Length of the train = Speed of the train x Time Taken
= (20 *24)m
= 480m
Hence the required length is 480 m.

Speed of the train = 204 km/hr.
We have to find the time in seconds, so convert the speed in the unit of m/sec.
Therefore 204 km/hr = 204 x 5/18 m/s
= 1020/18 m/s
Length of the train = 1800 meters.
we have to find the time taken by the train to cover 1800 meters at 1020/18 m/sec
Time = distance/speed
= 1800/(1020/18)sec
= (1800*18/1020)sec
= 32 sec (approx.)

Speed of the train = 25 m/s.
Length of the chunk = 0.8 km
= 800 meters
Time taken to cross the chunk = 6 minutes
= (6*60) seconds
= 360 seconds
Let the length of the train be y meters.
Time taken by the train to cover (800 + y) meters at 25 is 360 seconds
i.e., distance = speed x time
(800+y) = 25 x 360
800+y = 9000
y = 8200 m
i.e., y = 8.2 km
Hence the length of the train is 8.2 km

Length of the train = 560 m
Length of the platform = 340 m
Therefore, length of the train + length of the platform = 560 m + 340 m = 900 m
Time taken by the train to cross the platform = 45 sec
Therefore, speed of train = 900 m / 45 m/sec = 20 m/sec
To convert the speed from m/sec to km/hr, multiply by 18/5
Therefore, speed of the train = 20 × 18/5 km/hr = 72 km/hr

Length of the train = 240 m
Time taken to cross an object = 6 seconds
Speed of the train = Length of the train / Time taken to cross an object
= 240/6 m/s
= 40 m/s
Length of the pole = 162.5 m
Time taken to cross the pole= (Length of the train + Length of the pole) / Speed of the train
= (240 + 162.5)/40
= 402.5/40
= 10.06 seconds
Hence the answer is 10 seconds.

Given speed of the train = 63 km/hr
= 63*5/18 m/s =17.5m/s
Let the length of the pole = x mts
Given time taken to cover the distance of (510+ x)mts is 90 sec.
We know speed = distance/time m/s
17. 5 = 510+x/90
1575 = 510+x
x = 1065
Therefore the length of the pole is 1065 mts

Speed of the train = 90 km/hr
Converting the speed into m/sec
90 km/hr = (90* 5/18)m/s
= 25m/s
length of the train = distance travelled
we know distance = speed * time= (25*24)m
= 600 m
Distance travelled = Train length + telegraph post length
= (600 +1200)m
= 1800 m
Time = distance / speed
= ( 1800/25) sec
= 72 seconds
Hence the required answer is 72 seconds