(A) 2/3
(B) 3/2
(C) 5/6
(D) 6/5
Correct Option is: A
Let the event of the occurrence of a number that is even be ‘A’ and the event of the occurrence of a number
that is less than 3 be ‘B’. We need to find P(A or B).
P(A) = 3/6 (even numbers = 2,4,6)
P(B) = 2/6 (numbers less than 3 = 1,2)
P(A and B) = 1/6 (numbers that are both even and less than 3= 2)
Now, P(A or B) = P(A) + P(B) – P(A or B)
= 3/6 + 2/6 – 1/6
P(A or B) = 4/6=2/3